# Rate analysis for concrete – calculate quantity and cost

Rate analysis for concrete involves determining the quantities and costs of materials, labor, and equipment required for a specific volume of concrete. It typically includes factors such as:

1. Materials Cost: Cement, aggregates, water, and admixtures.

2. Labor Cost: Construction workers involved in mixing, placing, and finishing concrete.

3. Equipment Cost: Cost associated with concrete mixers, pumps, and other machinery.

4. Overhead and Profit: Additional costs for project management and profit margin.

Rate analysis for concrete – calculate quantity and cost, hi guys in this article we know about rate analysis of concrete m15, M10 and m7.5. Rate analysis comprise of sum of material cost, labour cost, overhead expenses, contractor profit and cost of equipment or tools. And also know about cost and quantity of cement, sand aggregate & water required for 1 cubic metre of m15 M10 and m7.5 concrete.

Rate analysis of concrete is average an estimate for quotation and billing purpose by mason, supervisor and contractor and for tendering use.

Rate Analysis for concrete :- It is a summary of all the cost involved in doing particular work or unit work like material cost, labour cost, overhead expenses, water charges & contractor profit. For rate analysis, the details about all the operation involved in carrying out the work should be available.

The quantities of materials cement sand aggregate and water are required and their cost should be known and the number of different categories of labours required and the capacity of doing work per labour and their wages per day should be known. These can be known only from the experience of particular work. Concrete structure is generally PCC por making Road,pavement, flooring, basement and etc

## Rate analysis for concrete work

Rate analysis for concrete work summary of all the quantity and cost of material, labours overhead expenses, contractor profit charges and water charges. Rate analysis for concrete is comprise of following:-

● 1) quantity and cost of material ( cement sand aggregate and water quantity and their cost)

● 2) water charges ( 1 tanker)

● 4) cost of equipment and tools (2%)

● 5) contractor profit (10%)

● 6) labour rate and cost.

### Rate analysis for 1 cum concrete of M15 (1:2:4)

M 15 grade of concrete have cement, sand and aggregate ratio 1:2:4 in which one part is cement, 2 part is sand and 3 part is aggregate. For quantity and cost calculation for m15 grade of concrete we should follow following steps:-

step 1, Dry volume :- we have wet volume of concrete is 1m3 and we have to convert wet volume into dry volume ,we will multiply 1.5 in wet volume.

Dry volume = 1.54 × 1 = 1.54 m3.

◆ step 2, Cement quantity:- we know that cement density is 1440 kg/m3 and 1 bag cement weight is 50 kg

Quantity of cement = 1/7 × 1.54 m3 × 1440 kg/m3 = 316.8 kg, no of bag cement for 1m3 m15 concrete = 316.8/50 = 6.3.

If rate of cement = INR 400 per bag, then cost of 6.3 bags cement = 6.3 ×400 = INR 2520.

◆ step 3, Sand quantity :- generally sand measured in CFT and 1m3 = 35.3147

Quantity of sand = 2/7 ×1.54 × 35.3147 = 15.5 cft, so 15.5 cft sand quantity required for 1m3 m15 grade of concrete

If market rate of sand is consider INR 50 per cft, then cost of 15.5 cft sand = 15.5 × 50 = INR 775, so cost of sand for 1m3 of m15 concrete = INR 775.

◆ step 4, Aggregate quantity :– generally aggregate measured in CFT and 1m3 = 35.3147

Quantity of aggregate = 4/7 ×1.54 × 35.3147 = 31 cft, so 31 cft aggregate quantity required for 1m3 m15 grade of concrete

If market rate of aggregate is consider INR 60 per cft, then cost of 31 cft aggregate = 31 × 60 = INR 1860, so cost of aggregate for 1m3 of m15 concrete = INR 1860.

◆ step 5, material cost :- quantity and cost of material required for 1 cubic metre of m15 grade of concrete is some cost of cement sand and aggregate

Sub total cost of material = cement cost + sand cost + aggregate cost = 2520 +775 + 1860 = INR 5155.

◆ step 6, labour rate and charges :- consider one mason and 2 helper completed 1 cubic metre of concrete work in 8 hour, per mason rate INR 600 and per Helper rate 400,then cost of labour in concreting work = 600 +(2×400) = INR 1400.

Sub total cost = 5155 + 1400 = INR 6555

◆ step 7, water charges:- quantity of water required in concreting work used for preparing of mix and curing, consider 1.5% cost of water, then 1.5% of 6555 = INR 98

Sub total cost = 6555 + 98 = INR 6653

◆ step 8, overhead expenses :- consider 2% overhead expenses,then 2% of 6555 = INR 131.

Sub total cost = 6653 + 131 = INR 6784

◆ step 9, cost of equipment and tools :– consider cost of equipment or tools is 1.5 %,then 1.5% of 6555 = INR 98

Sub total cost = 6784 + 98 = INR 6882

◆ step 10, contractor profit :- consider contractor profit is 10%, then 10% of 6555 = INR 655

Total cost = 6882 + 655 = INR 7537.

Ans. INR 7537 is cost and rate analysis for 1 cum concrete of M15 (1:2:4).

◆ step 11 : rate per sq m for concrete m15, consider thickness of concrete structure is 150mm thick so Area of concrete structure in square metre = 1m3/0.15m = 6.67,

6.67 m2 concrete structure cost = INR 7537, so rate per sq m for concrete M15 = 7537/6.67 = INR 1130.

◆ step 12 :-  rate per sq feet for concrete m15,consider thickness of concrete structure is 6 inch (0.5 ft) thick and 1m3 = 35.3147 cft so Area of concrete structure in square feet = 35.3147/0.5 = 70.6 sq ft

70.6 sq ft concrete structure cost = INR 7537, so rate per sq ft for concrete M15 = 7537/70.6 = INR 107.

READ MORE:- RATE ANALYSIS OF AAC BLOCK MASONARY WORK

◆ conclusion:- Rate analysis for concrete

● 1) Rate per cum for concrete M15 = INR 7537

● 2) Rate per sq m for concrete M15 = INR 1130

● 3) Rate per sq ft for concrete M15 = INR 107.

### Rate analysis for 1 cum concrete of M10 (1:3:6)

M10 grade of concrete have cement, sand and aggregate ratio 1:3:6 in which one part is cement, 3 part is sand and 6 part is aggregate. For quantity and cost calculation for m10 grade of concrete we should follow following steps:-

◆ step 1, Dry volume :- we have wet volume of concrete is 1m3 and we have to convert wet volume into dry volume ,we will multiply 1.54 in wet volume.

Dry volume = 1.54 × 1 = 1.54 m3.

◆ step 2, Cement quantity:- we know that cement density is 1440 kg/m3 and 1 bag cement weight is 50 kg

Quantity of cement = 1/10 × 1.54 m3 × 1440 kg/m3 = 222 kg, no of bag cement for 1m3 m10 concrete = 222/50 = 4.44.

If rate of cement = INR 400 per bag, then cost of 4.44 bags cement = 4.44 ×400 = INR 1776.

◆ step 3, Sand quantity :- generally sand measured in CFT and 1m3 = 35.3147

Quantity of sand = 3/10 ×1.54 × 35.3147 = 16.3 cft, so 16.3 cft sand quantity required for 1m3 m10 grade of concrete

If market rate of sand is consider INR 50 per cft, then cost of 16.3 cft sand = 16.3 × 50 = INR 815, so cost of sand for 1m3 of m10 concrete = INR 815.

◆ step 4, Aggregate quantity :- generally aggregate measured in CFT and 1m3 = 35.3147

Quantity of aggregate = 6/10 ×1.54 × 35.3147 = 32.6 cft, so 32.6 cft aggregate quantity required for 1m3 m10 grade of concrete

If market rate of aggregate is consider INR 60 per cft, then cost of 32.6 cft aggregate = 32.6 × 60 = INR 1956 , so cost of aggregate for 1m3 of m10 concrete = INR 1956.

◆ step 5, material cost :- quantity and cost of material required for 1 cubic metre of m10 grade of concrete is some cost of cement sand and aggregate

Sub total cost of material = cement cost + sand cost + aggregate cost = 1776 +815 + 1956 = INR 4547.

◆ step 6, labour rate and charges :- consider one mason and 2 helper completed 1 cubic metre of concrete work in 8 hour, per mason rate INR 600 and per Helper rate 400,then cost of labour in concreting work = 600 +(2×400) = INR 1400.

Sub total cost = 4547 + 1400 = INR 5947

◆ step 7, water charges:- quantity of water required in concreting work used for preparing of mix and curing, consider 1.5% cost of water, then 1.5% of 5947 = INR 89

Sub total cost = 5947 + 89 = INR 6036

◆ step 8, overhead expenses :- consider 2% overhead expenses,then 2% of 5947 = INR 119.

Sub total cost = 6036 + 119 = INR 6155

◆ step 9, cost of equipment and tools :- consider cost of equipment or tools is 1.5 %,then 1.5% of 5947 = INR 89

Sub total cost = 6155 + 89 = INR 6244

◆ step 10, contractor profit :- consider contractor profit is 10%, then 10% of 5947 = INR 595

Total cost = 6244 + 595 = INR 6839.

Ans. INR 6839 is cost and rate analysis for 1 cum concrete of M10 (1:3:6).

◆ step 11 : rate per sq m for concrete m10, consider thickness of concrete structure is 150mm thick so Area of concrete structure in square metre = 1m3/0.15m = 6.67,

6.67 m2 concrete structure cost = INR 6839, so rate per sq m for concrete M10 = 6839/6.67 = INR 1025.

◆ step 12 :-  rate per sq feet for concrete m10,consider thickness of concrete structure is 6 inch (0.5 ft) thick and 1m3 = 35.3147 cft so Area of concrete structure in square feet = 35.3147/0.5 = 70.6 sq ft

70.6 sq ft concrete structure cost = INR 6839, so rate per sq ft for concrete M10 = 6839/70.6 = INR 97.

READ MORE : RATE ANALYSIS OF 1m3 BRICKWORK

◆ conclusion:- Rate analysis for concrete

● 1) Rate per cum for concrete M10 = INR 6839

● 2) Rate per sq m for concrete M10 = INR 1025

● 3) Rate per sq ft for concrete M10 = INR 97.

### Rate analysis for 1 cum concrete of M7.5 (1:4:8)

M7.5 grade of concrete have cement, sand and aggregate ratio 1:4:8 in which one part is cement, 4 part is sand and 8 part is aggregate. For quantity and cost calculation for m7.5 grade of concrete we should follow following steps:-

◆ step 1, Dry volume :- we have wet volume of concrete is 1m3 and we have to convert wet volume into dry volume ,we will multiply 1.54 in wet volume.

Dry volume = 1.54 × 1 = 1.54 m3.

◆ step 2, Cement quantity:- we know that cement density is 1440 kg/m3 and 1 bag cement weight is 50 kg

Quantity of cement = 1/13 × 1.54 m3 × 1440 kg/m3 = 170 kg, no of bag cement for 1m3 m7.5 concrete = 170/50 = 3.4.

If rate of cement = INR 400 per bag, then cost of 3.4 bags cement = 3.4 ×400 = INR 1360.

◆ step 3, Sand quantity :- generally sand measured in CFT and 1m3 = 35.3147

Quantity of sand = 4/13 ×1.54 × 35.3147 = 16.73 cft, so 16.73 cft sand quantity required for 1m3 m7.5 grade of concrete

If market rate of sand is consider INR 50 per cft, then cost of 16.73 cft sand = 16.73 × 50 = INR 837, so cost of sand for 1m3 of m7.5 concrete = INR 837.

◆ step 4, Aggregate quantity :- generally aggregate measured in CFT and 1m3 = 35.3147

Quantity of aggregate = 8/13 ×1.54 × 35.3147 = 33.47 cft, so 33.47 cft aggregate quantity required for 1m3 m7.5 grade of concrete

If market rate of aggregate is consider INR 60 per cft, then cost of 33.47 cft aggregate = 33.47 × 60 = INR 2008, so cost of aggregate for 1m3 of m7.5 concrete = INR 2008.

◆ step 5, material cost :- quantity and cost of material required for 1 cubic metre of m7.5 grade of concrete is some cost of cement sand and aggregate

Sub total cost of material = cement cost + sand cost + aggregate cost = 1360 +837 + 2008 = INR 4205.

◆ step 6, labour rate and charges :- consider one mason and 2 helper completed 1 cubic metre of concrete work in 8 hour, per mason rate INR 600 and per Helper rate 400,then cost of labour in concreting work = 600 +(2×400) = INR 1400.

Sub total cost = 4205 + 1400 = INR 5605

◆ step 7, water charges:- quantity of water required in concreting work used for preparing of mix and curing, consider 1.5% cost of water, then 1.5% of 5605 = INR 84

Sub total cost = 5605 + 84 = INR 5689

◆ step 8, overhead expenses :- consider 2% overhead expenses,then 2% of 5605 = INR 112.

Sub total cost = 5689 + 112 = INR 5801

◆ step 9, cost of equipment and tools :- consider cost of equipment or tools is 1.5 %,then 1.5% of 5605 = INR 84

Sub total cost = 5801 + 84 = INR 5885

◆ step 10, contractor profit :– consider contractor profit is 10%, then 10% of 5605 = INR 560

Total cost = 5885 + 560 = INR 6445.

Ans. INR 6445 is cost and rate analysis for 1 cum concrete of M7.5 (1:4:8).

◆ step 11 : rate per sq m for concrete m7.5, consider thickness of concrete structure is 150mm thick so Area of concrete structure in square metre = 1m3/0.15m = 6.67,

6.67 m2 concrete structure cost = INR 6445, so rate per sq m for concrete M7.5 = 6445/6.67 = INR 966.

◆ step 12:- rate per sq feet for concrete m7.5,consider thickness of concrete structure is 6 inch (0.5 ft) thick and 1m3 = 35.3147 cft so Area of concrete structure in square feet = 35.3147/0.5 = 70.6 sq ft

70.6 sq ft concrete structure cost = INR 6445, so rate per sq ft for concrete M7.5 = 6445/70.6 = INR 91.

◆ conclusion:- Rate analysis for concrete

● 1) Rate per cum for concrete M7.5 = INR 6445

● 2) Rate per sq m for concrete M7.5 = INR 966

● 3) Rate per sq ft for concrete M7.5 = INR 91.

Note:-

1) Shuttering component is not considered as the quantity of shuttering for the slab, beam, column and foundation shall be different.

2) The material rates considered in this rate analysis are exclusive of GST.

3) The material and labour rates may vary depending on the site condition & type of project.