# How to calculate cutting length of triangular stirrups

How to calculate cutting length of triangular stirrups,Cutting length of triangular stirrups,in this topic we know about how to calculate cutting length of triangular stirrups. Another word stirrups is also known as ring or shear reinforcement.

It is closed loop of reinforcements used to hold the main reinforcement in RCC structure like column and beam. The triangular Ring used in column provide lateral support to the the main bar against buckling it is used at proper interval to beam and column to prevent them from buckling.

Also they protect RCC structure from collapsing during seismic activity like earthquake. It is used to resist lateral shear stress and diagonal tension stress in RCC structure and provide stability to the reinforcement of Steel bar.let us discuss about how to calculate cutting length of triangular stirrups.

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●How to calculate cutting length of triangular stirrup

## Cutting length of triangular stirrups

It is total length of triangular closed ring having hook at one reinforcement used in column. suppose we have given following

Size of column = 600×500 mm

Length =600 mm

Width =500mm

Clear cover = 40 mm

Dia of stirrups=8mm

Dia of steel in column=16mm

When we use 10 mm and 12 mm die of Steel bar in column we have clear cover is equal to 25 mm and when we use more than 12 mm die of Steel bar in column we have clear cover is equal to 40 mm.

Cutting length = perimeter of ring + hook length – bend elongation

1) first we calculate perimeter of stirrups

Perimeter= (a+2b)

We have given length of column

Length=600 mm.

First we calculate length of a that is base of triangular stirrups

Length of a =600_2cover_2×4(half dia of stirrups at both sides)

a = 600_2×40_2×4 mm

Length of a = 512 mm

For calculating the value of b sides first we have to calculate height of triangular stirrup

We have given width=500mm

H =500_2cover_2×4(half dia of stirrups at both sides)

H = 500_2×40_2×4

Height =412 mm

Now we have a=512 mm and H=412mm
Now calculate value of b by Pythagorus theorem in which b is hypotonuse a/2 is base and H is perpendicular

a/2 = 512/2 =256 mm

b = √ H^2+(a/2)^2

b=√ (412)^2+(256)^2

length of b =√235280

Length of b =485 mm

Now perimeter = (a+2b)

Perimeter = 512+2×485 mm

Perimeter = 1482 mm

### calculation of hook length of  traingular stirrups

In triangular ring it has two hook length , minimum size of hook length is equal to 75 mm or 10d where d is dia of bar

Hook length = 10d ,but in triangular ring it has two hook

hook length = 2×10d

Hook length = 2×10×8=160mm

### bend elongation calculation in traingular stirrup

In closed triangular ring reinforcement we have 4 bend at 135 degrees.

● bend angle 45° = 1d
● bend angle 90° = 2d
● bend angle 135°= 3d

Bend elongation = 4bend at 135°

Bend = (4×3d)

Bend elongation = 4×3×8 = 96 mm

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● now cutting length of triangular stirrup

Cutting length = perimeter of ring + hook length – bend elongation

Cutting L = 1482+160_96 mm

Cutting length =1642 mm _96mm

Cutting length=1546 mm

Hence cutting length of triangular stirrups